DOL Median (Evansville, IN)
$82,467
vs National
+30.9%
National: $63,000BLS Median (area)
N/A
COL-Adjusted
$90,623
Purchasing power equiv.Salary Comparison
This Location (DOL)
$82,467
+30.9% vs national
National Average (DOL)
$63,000
Baseline
BLS Estimate (This Area)
N/A
No comparison
Purchasing Power Analysis
A Food Scientists and Technologists in Evansville, IN earns $82,467 in nominal terms, which is 30.9% above the national average of $63,000. After adjusting for the local cost of living (index 91.0 vs national 100), this is equivalent to $90,623 in national-average purchasing power.
Tax differences are not included. Only cost-of-living index adjustments are applied.
Top Employers in Evansville, IN
| Employer | Median Salary | Filings |
|---|---|---|
| Mead Johnson & Company, LLC | $85,000 | 13 |
| MEAD JOHNSON AND COMPANY, LLC | $49,525 | 1 |
Explore More
Top-Paying Metros for Food Scientists and Technologists
Lewis Center, OH · $180,000Pennsauken, NJ · $180,000Reno, NV · $178,000PAICINES, CA · $172,000Springdale, AR · $160,000Top-Paying Roles in Evansville, IN
Medical Scientists, Except Epidemiologists · $300,000Chief Executives · $280,000Dentists, General · $182,000Marketing Managers · $165,000Architectural and Engineering Managers · $118,019Frequently Asked Questions
How much does a Food Scientists and Technologists make in Evansville, IN?
The median Food Scientists and Technologists salary in Evansville, IN is $82,467 based on 12 DOL filings.
Is Evansville, IN a good place to work as a Food Scientists and Technologists?
A Food Scientists and Technologists in Evansville, IN earns 30.9% more than the national median of $63,000, or $90,623 after adjusting for the local cost of living.
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Source: US Department of Labor, Office of Foreign Labor Certification (OFLC) public disclosure files (PERM Form ETA-9089 and LCA Form ETA-9035), and US Bureau of Labor Statistics Occupational Employment and Wage Statistics (OEWS). Salary figures represent employer filings and government survey estimates, not individual worker pay.